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For a CE transistor amplifier the audio ...

For a CE transistor amplifier the audio signal voltage across the collector resistance of 2.0 `komega` is 2.0 V suppose the current amplification factor of the transistor is 100 what should be the value of `R_(B)` in series with `V_(BB)` 10 times the signal current also calculate the DC drop across the collector resistance

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To solve the problem, we need to find the value of \( R_B \) in series with \( V_{BB} \) and calculate the DC drop across the collector resistance. ### Step 1: Calculate the Signal Current at the Collector The audio signal voltage across the collector resistance \( R_C \) is given as 2.0 V, and the collector resistance \( R_C \) is 2.0 kΩ. Using Ohm's law, the current \( I_C \) through the collector resistance can be calculated as: \[ I_C = \frac{V_{C}}{R_C} = \frac{2.0 \, \text{V}}{2.0 \, \text{kΩ}} = \frac{2.0}{2000} = 0.001 \, \text{A} = 1 \, \text{mA} ...
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