A p-n photodiode is fabricated from a semiconductor with band gap of 2.8 eV can it detect a wavelength of 6000 nm

Explanation

To determine if a p-n photodiode fabricated from a semiconductor with a band gap of 2.8 eV can detect a wavelength of 6000 nm, we need to follow these steps:

### Step 1: Understand the relationship between wavelength and energy
The energy of a photon can be calculated using the formula:
\[ E = \frac{hc}{\lambda} \]
where:
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