The number of silicon atoms per `m^(3) is 5xx10^(28)`. This is doped simultaneously with `5xx10^(22)` atoms per `m^(3)` of Arsenic and `5xx10^(20) per m^(3)` atoms of indium. Calculate the number of electrons and holes. Given that `n_(i)=1.5xx10^(16)m^(-3)`. Is the material n-type or p-type?

Explanation

Given `n=5 xx 10^(22) m^(-3)`
`N_(A) = 5xx 10^(20 m^(-3)`
Since `n_(theta) - n_(0) = N_(D) - N_(A)`
and `n_(h) = (n_(1)^(2))/( n_(0)) = (2.25 xx 10^( 32))/( 4.95 xx 10^(22))`
or `n_(b) = (2.25)/( 4.95) xx 10^(10)`
`n_(h) = 4.55 xx 10^(9)`
Since `n_(0) gt n_(b)` so the material is n- type .