Which of the following has maximum mass
(a) 2.6 gram atoms of sulphur (b) 2.6 gram molecules of sucrose (`C_(12)H_(22)O_(11)`) (c) 2.6 g of iodine

Explanation

To determine which option has the maximum mass, we will calculate the mass for each of the given options step by step.

### Step 1: Calculate the mass of 2.6 gram atoms of sulfur.

1. **Understanding gram atoms**: 1 gram atom of sulfur (S) is equivalent to 1 mole of sulfur, which has a molar mass of approximately 32 g/mol.
2. **Calculating mass for 2.6 gram atoms**:
\[ \text{Mass of 2.6 gram atoms of S} = 2.6 \, \text{moles} \times 32 \, \text{g/mol} = 83.2 \, \text{grams} \]

### Step 2: Calculate the mass of 2.6 gram molecules of sucrose (C₁₂H₂₂O₁₁).

1. **Understanding gram molecules**: 1 gram molecule of sucrose is equivalent to 1 mole of sucrose, which has a molar mass of approximately 342 g/mol.
2. **Calculating mass for 2.6 gram molecules**:
\[ \text{Mass of 2.6 gram molecules of C}_{12}H_{22}O_{11} = 2.6 \, \text{moles} \times 342 \, \text{g/mol} = 889.2 \, \text{grams} \]

### Step 3: Consider the mass of 2.6 grams of iodine.

1. **Given mass**: The mass of iodine is directly given as 2.6 grams.

### Step 4: Compare the masses calculated.

- Mass of 2.6 gram atoms of sulfur: **83.2 grams**
- Mass of 2.6 gram molecules of sucrose: **889.2 grams**
- Mass of 2.6 grams of iodine: **2.6 grams**

### Conclusion:

The option with the maximum mass is **2.6 gram molecules of sucrose (C₁₂H₂₂O₁₁)**, which has a mass of **889.2 grams**.

---