Calculate the number of molecules and number of atoms present in 5.60 L of ozone (`O_(3)`) at N.T.P.

Explanation

To solve the problem of calculating the number of molecules and atoms present in 5.60 L of ozone (O₃) at N.T.P (Normal Temperature and Pressure), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Volume of One Mole at NTP:**
At NTP, one mole of any gas occupies a volume of 22.4 liters.

2. **Calculate the Number of Moles in 5.60 L of Ozone:**
We can use the unitary method to find out how many moles are present in 5.60 L of ozone.
\[ \text{Number of moles} = \frac{\text{Volume of gas}}{\text{Volume of 1 mole}} = \frac{5.60 \, \text{L}}{22.4 \, \text{L/mol}} = 0.25 \, \text{moles} \]

3. **Calculate the Number of Molecules:**
Using Avogadro's number, which is \(6.022 \times 10^{23}\) molecules per mole, we can find the number of molecules in 0.25 moles of ozone.
\[ \text{Number of molecules} = \text{Number of moles} \times \text{Avogadro's number} = 0.25 \, \text{moles} \times 6.022 \times 10^{23} \, \text{molecules/mole} = 1.506 \times 10^{23} \, \text{molecules} \]

4. **Calculate the Number of Atoms:**
Each molecule of ozone (O₃) contains 3 oxygen atoms. Therefore, to find the total number of atoms, we multiply the number of molecules by 3.
\[ \text{Number of atoms} = \text{Number of molecules} \times 3 = 1.506 \times 10^{23} \, \text{molecules} \times 3 = 4.518 \times 10^{23} \, \text{atoms} \]

### Final Results:
- Number of molecules of ozone in 5.60 L at NTP: \(1.506 \times 10^{23}\)
- Number of atoms in 5.60 L of ozone at NTP: \(4.518 \times 10^{23}\)