How many moles of `NaOH` are contained in `27 mL` of `0.15 M NaOH`?

Answer

D

Explanation

Moalrity `=("Moles of NaOH")/("Vol. of solution") xx 1000`
Molarity =0.15 M, vol of solution = 27 mL
`therefore 0.15 = ("Moles of NaOH")/27 xx 1000`
`therefore` Moles of NaOH `=(27 xx 0.15)/1000`
= 0.00405 mol