In a reaction vessel `0.184 g` of `NaOH` is required to be added for completing the reaction. How many millilitre of `0.150M NaOH` solution should be added for this requirements?

Answer

C

Explanation

Molecular mass of NaOH = 23 + 16 +1 =40
1 M solution of NaOH contains = `40 g L^(-1)`
0.150 M solution of NaOH contains `4.0 xx 0.150`
`= 6 g L^(-1)`
6 g of NaOH is present in 1000 mL
0.184 g of NaOH is present in
`=(1000 xx 0.184)/6 = 30.7` mL of NaOH.