1.615 g of anhydrous `ZnSO_(4)` was left in moist air. After a few days its weight was found to be 2.875 g. What is the molecular formula of hydrated salt ? (At. Mass: Zn=65.5, S=32, O=16, H=1)

Explanation

To determine the molecular formula of the hydrated salt formed when anhydrous ZnSO₄ is left in moist air, we will follow these steps:

### Step 1: Calculate the weight of water absorbed
The initial weight of anhydrous ZnSO₄ is given as 1.615 g, and the final weight after absorbing moisture is 2.875 g.

To find the weight of water absorbed:
\[
\text{Weight of water} = \text{Final weight} - \text{Initial weight} = 2.875 \, \text{g} - 1.615 \, \text{g} = 1.260 \, \text{g}
...