Calculate the amount of carbon dioxide that could be produced when
a. `1` mol of carbon is burnt in air
b. `1` moles of carbon is brunt in `16 g` of dioxygen.
`2` moles of carbon are burnt in `16 g` of dioxygen.

Explanation

`C + O_(2) to CO_(2)`
1 mol of carbon reacts with 1 mol of oxygen to form 1 mole of `CO_(2)` .
(i) 1 mol of `CO_(2)` or 44 g of `CO_(2)` .
(ii) Since 16 g of dioxygen i.e. 0.5 mol of `O_(2)` are present, it is a limiting reagent. 0.5 mol of `O_(2)` will form 0.5 mol of `CO_(2)` i.e. 22 g.
(iii) 16 g or 0.5 mol of `O_(2)` is limiting reagent. 0.5 mol of `CO_(2)` will form 0.5 mol of `CO_(2)` i.e. 22 g