Lithium oxide is used to remove water from air according to the following reaction:
`Li_(2)O(s) + H_(2)O(g) to 2LiOH(s)`
90 kg of water is to be removed and 45 kg of `Li_(2)O` is available.
Calculate the maximum amount of water that will be removed.

Explanation

To solve the problem of how much water can be removed using lithium oxide (Li₂O), we will follow these steps:

### Step 1: Write the balanced chemical equation
The reaction given is:
\[ \text{Li}_2\text{O(s)} + \text{H}_2\text{O(g)} \rightarrow 2\text{LiOH(s)} \]

### Step 2: Calculate the moles of water to be removed
We need to remove 90 kg of water. First, we convert this mass into grams:
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