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A solution has 25% of water, 25% ethano...

A solution has ` 25% `of water,` 25% `ethanol and ` 50% `acetic acid by mass. Calculate the mol e fraction of each component.

A

water = 0.502

B

Ethanol = 0.302

C

Acetic acid = 0.196

D

Ethanol + acetic acid = 4.098

Text Solution

Verified by Experts

The correct Answer is:
A, D
Moles of water `=25/18 = 1.388`
Moles of ethanol `=25/46 = 0.543`
Moles of acetic acid `=50/60 = 0.833`
Total moles `=1.388 + 0.543 + 0.833 = 2.764`
x(water) `=1.388/2.764 = 0.502`
x(ethanol) = 0.196
x(acetic acid) = 0.302
x(ethanol) + x(acetic acid) = 0.498
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