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According to Bohr's theory , the electro...

According to Bohr's theory , the electronic energy of hydrogen atom in the `n^(th)` Bohr's orbit is given by
`E_(n) = (-21.76 xx 10^(-19))/(n^(2)) J`
Calculate the longest wavelength of electron from the third Bohr's orbit of the `He^(o+)` ion

Text Solution

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For hydrogen like ion, i.e., `He^(+)`, the relation is :
`E_n = (21.76 xx 10^(-19) Z^2)/(n^2) J` per atom
where Z is atomic number, For `He^+ ,Z = 2`
Energy of `He^(+)` ion in third orbit `(n = 3)`
`E_3 = (21.76 xx 10^(-19) xx 4)/(3^2) J`
Energy required to removed an electron fro third Bohr orbit of `He^+` ion is :
`Delta E = E_(oo) - E_3`
`= 0 - (-(21.76 xx 10^(-19) xx 4)/(9)) J`
`= 9.67 xx 10^(-19) J`
Now, `Delta E = (hc)/(lambda)`
or `lambda = (hc)/(Delta E) = (6.626 xx 10^(-34) xx 3.0 xx 10^8)/(9.67 xx 10^(-19) J)`
`= 2.055 xx 10^(-7) m = 205.5 nm`.
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