Home
Class 11
CHEMISTRY
Calculate the wavelength of an electron ...

Calculate the wavelength of an electron moving with a velocity fo ` 2. 05 xx 10^7 ms^(-1)`.

Text Solution

Verified by Experts

According to de - Broglie wavelength,
`lambda = h/(mv)`
`m = 9.11 xx 10^(-31) kg`,
`h = 6.63 xx 10^(-34) kg m^2 s^(-1)`
`v = 2.05 xx 10^7 ms^(-1)`
`:. lambda = (6.63 xx 10^(34) kg m^2 s^(-1))/((9.11 xx 10^(-31) kg) xx (2.05 xx 10^7 ms^(-1)))`
`= 3.55 xx 10^(-11) m`.
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    MODERN PUBLICATION|Exercise PRACTICE PROBLEMS|62 Videos
  • STRUCTURE OF ATOM

    MODERN PUBLICATION|Exercise Conceptual Questions 1|17 Videos
  • STATES OF MATTER : GASES AND LIQUIDS

    MODERN PUBLICATION|Exercise UNIT PRACTICE TEST|13 Videos
  • THERMODYNAMICS

    MODERN PUBLICATION|Exercise Unit Practice Test|12 Videos

Similar Questions

Explore conceptually related problems

The wavelength of an electron moving with velocity of 10^(7)ms^(-1) is

What will be de Broglie's wavelength of an electron moving with a velocity of 1.2 xx 10^(5) ms^(-1) ?

Calculate the wavelength associated with an electron moving with a velocity of 10^(3) m s^(-1) .

A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3 xx 10^(6) ms^(-1) . The velocity of the particle is

Calculate the de Broglie wavelength of an electron moving with a velocity of 0.3c. Rest mass of an electron is 9.1xx10^(-31)kg.

The de-Broglie wavelength of an electron moving with a velocity 1.5 xx 10^(8)ms^(-1) is equal to that of a photon. The ratio of the kinetic energy of the electron to that of the photon is:

A particle of mass 1mg has the same wavelength as an electron moving with a velocity of 3xx10^6 ms^(-1) . What is the velocity of the particle ? (Take mass of the electron =9xx10^(-31) kg )