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Calculate the kinetic energy of a movin...

Calculate the kinetic energy of a moving electron which has wavelength of 4.8 pm.

Text Solution

Verified by Experts

According to de-Broglie equation,
`lambda = h/(mv)`
`lambda = 4.8 pm = 4.8 xx 10^(-12) m, m = 9.11 xx 10^(-31) kg`
`4.8 xx 10^(-12) m = (6.63 xx 10^(-34) kg m^2 s^(-1))/(9.11 xx 10^(-31) kg xx v)`
or `v = (6.63 xx 10^(-34) kg m^2 s^(-1))/((4.8 xx 10^(-12) m) xx (9.11 xx 10^(-31)kg))`
`= 1.516 xx 10^8 m s^(-1)`
`:.` Kinetic energy = `1/2 mv^2`
`= 1/2 xx (9.11 xx 10^(-31) kg)`
`xx (1.516 xx 10^8 ms^(-1))^(2)`
`= 1.05 xx 10^(-14) kg m^2 s^(-2)`
or ` = 1.05 xx 10^(-14) J`
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