The orbital angular momentum for an electron revolving in an orbit for an s-electron is

Options

A. zero
B. `h/(2 pi)`
C. `sqrt(2) h/(2pi)`
D. `1/2 cdot h/(2pi)`

Explanation

To find the orbital angular momentum for an electron in an s-orbital, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Orbital Angular Momentum**:
The orbital angular momentum (L) of an electron in an atom is given by the formula:
\[ L = \frac{h}{2\pi} \sqrt{l(l + 1)} \]
where \(h\) is Planck's constant and \(l\) is the azimuthal quantum number.

2. **Identify the Azimuthal Quantum Number for s-Electrons**:
For s-electrons, the azimuthal quantum number \(l\) is equal to 0. This is because s-orbitals correspond to \(l = 0\).

3. **Substitute the Value of \(l\) into the Formula**:
Now, we substitute \(l = 0\) into the formula for orbital angular momentum:
\[ L = \frac{h}{2\pi} \sqrt{0(0 + 1)} = \frac{h}{2\pi} \sqrt{0} = \frac{h}{2\pi} \cdot 0 = 0 \]

4. **Conclusion**:
Therefore, the orbital angular momentum for an electron in an s-orbital is:
\[ L = 0 \]

### Final Answer:
The orbital angular momentum for an electron revolving in an orbit for an s-electron is **0**.