The energies `E_1` and `E_2` of two radiations are `25 eV` and `50 e V` respectively. The relation between their wavelengths, i.e., `lamda_1` and `lamda_2` will be.

Options

A. `lambda_1 = lambda_2`
B. `lambda_1 = 2 lambda_2`
C. `lambda_1 = 4lambda_2`
D. `lambda_1 = 1/2 lambda_2`

Answer

B

Explanation

`E_1 = (hc)/(lambda_1) , E_2 = (hc)/(lambda_2)`
`(E_1)/(E_2) = (lambda_2)/(lambda_1) " or " (lambda_2)/(lambda_1) = 25/50 = 1/2`
`:. lambda_1 = 2lambda_2`.