The correct set of four quantum numbers for valence electrons of rubidium atom (Z=37) is

Options

A. `5, 1,1, + 1//2`
B. `6,0,0,+1//2`
C. `5, 0,0,+1//2`
D. `5,1,0,+1//2`

Answer

C

Explanation

The electroic configuration of Rb is `[Ar] 3d^10 4s^2 4p^6 5s^(1)`. The outermost electron is `5s^(1)`.
Quantum numbers : `5, 0, 0, +1/2`.