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Energy of an electron is givem by E = - ...

Energy of an electron is givem by `E = - 2.178 xx 10^-18 J ((Z^2)/(n^2))`. Wavelength of light required to excited an electron in an hydrogen atom from level `n = 1` to `n = 2` will be
`(h = 6.62 xx 10^-34 Js` and `c = 3.0 xx 10^8 ms^-1`).

A

`8.500 xx 10^(-7)m`

B

`1.214 xx 10^(-7) m`

C

`2.816 xx 10^(-7) m`

D

`6.500 xx 10^(-7) m`

Text Solution

Verified by Experts

The correct Answer is:
B

`E_1 = -2.178 xx 10^(-18) xx (1^2)/(1^2) = -2.178 xx 10^(-18) J`
`E_2 = -2.178 xx 10^(-18) xx (1^2)/(2^2) = -5.445 xx 10^(-19)J`
Energy required to excite electron from `n = 1` to `n = 2`,
`DeltaE = -5.445 xx 10^(-19) - (-2.178 xx 10^(-18))`
`= 16.335 xx 10^(-19) J`
`(hc)/(lambda) = 16.335 xx 10^(-19)`
`lambda = (6.63 xx 10^(-34) xx 3.0 xx 10^8)/(16.335 xx 10^(-19))`
`= 1.217 xx 10^(-7)m`.
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