The shortest wavelength in hydrogen spectrum of Lyman series when `R_(H)=109678 cm^(-1)` is :-

Options

A. `1002.7 Å`
B. `1215.67 Å`
C. `1127.30 Å`
D. `911.7Å`

Answer

D

Explanation

`1/lambda = R_H[1/(n_1^2) - 1/(n_2^2)]`
Shortest wavelength line in hydrogen spectrum of Lyman series is from `n_2 = oo and n_1 = 1`
`1/lambda = 109678 [1/((1)^2) -1/(oo^2)] = 109678 cm^(-1)`
or `lambda = 1/(109678) cm = 9.11 xx 10^(-6) cm`
`= 911 xx 10^(-10) m " or " 911 Å`.