The correct set of four quantum numbers for valence electrons of rubidium atom (Z=37) is

Options

A. `5,0,1, + 1/2`
B. `5,0,0, +1/2`
C. `5,1,0, + 1/2`
D. `5,1,1,+1/2`

Answer

B

Explanation

The electronic configuration of `Rb (Z = 37)` is
`1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^6 5s^1`
Valence electron is `5 s^1`
Quantum numbers,
`n = 5,l = 0, m = 0, s = + 1//2`.