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Write down all the four quantum numbers ...

Write down all the four quantum numbers for (i) 19th electron of `._(24)Cr` (ii) 21st electron for `._(21)Sc`.

A

`(4, 1, -1, +1/2)`

B

`(4,0,0,+1/2)`

C

`(3,2,0,-1/2)`

D

`(3,2,-2, + 1/2)`

Text Solution

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The correct Answer is:
B
Electronic configuration of `Cr(Z = 24)`
`Cr : 1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5`
19th electron is present in 4s-orbital
For 4s orbital , `n = 4, l = 0, m = 0, s = +- 1//2`.
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