The de Broglie wavelenght `(lambda)` associated with a photoelectron varies with the frequency `(v)` of the incident radiation as,[`v_(0)` is threshold frequency]:

Options

A. `lambda prop (1)/((v - v_0)^(3/2))`
B. `lambda prop (1)/((v - v_0)^(1/2))`
C. `lambda prop (1)/((v - v_0)^(1/4))`
D. `lambda prop (1)/((v - v_0))`

Answer

B

Explanation

de-Broglie wavelength
`lambda = h/(sqrt(2 K.E. xx m))`
Now for photoelectronemission,
`hv = hv_0 + KE`
`KE = hv - hv_0`
`:. lambda = h/(sqrt(2m(hv - hv_0)))`
or `" " lambda = h/(sqrt(2mh(v - v_0)))`
or `lambda prop 1/((v - v_0)^(1//2))`.