For emission line of atomic hydrogen from `n_(i)=8` to `n_(f)=n,` the plot of wave number `(barv)` against`((1)/(n^(2)))` will be (The Rydberg constant, `R_(H)` is in wave number unit)

Options

A. Linear with slope - `R_H`
B. Linear with intercept - `R_H`
C. Non linear
D. Linear with slope `R_H`

Answer

D

Explanation

`1/lambda = barv = R_H Z^2(1/(n_1^2) - 1/(n_2^2))`
`barv = R_H xx (1/(n_f^2) - 1/(8^2)) (Z = 1 "for" H)`
`barv = R_H xx 1/(n_f^2) - (R_H)/(64)`
The plot of `barv` against `1/(n_f^2)` will be linear with slope `= R_H`.