The enthalpy of formation of gaseous iodine is `62.5 kJ "mol"^(-1)`. What is the enthalpy of sublimation of iodine at `25^(@)C`?

Explanation

To find the enthalpy of sublimation of iodine at \(25^\circ C\), we can follow these steps:

### Step 1: Understand the Definitions
- **Enthalpy of Formation**: This is the change in enthalpy when one mole of a compound is formed from its elements in their standard states.
- **Enthalpy of Sublimation**: This is the change in enthalpy when one mole of a solid substance is converted directly into a gas.

### Step 2: Identify the Given Information
- We are given the enthalpy of formation of gaseous iodine, which is \(62.5 \, \text{kJ/mol}\).
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