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In a process, 701 J of heat is absorbed ...

In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system.What is the change in internal energy for the process?

Text Solution

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Heat absorbed by the system = 701 J
or q = 701 J
Work done by the system = 394 J
or w = -394 J
According to first law of thermodynamics
`DeltaU = q + w`
`DeltaU = 701 -394 = 307 J`.
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