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For the reaction at 298 K 2A+B rarr C ...

For the reaction at `298 K`
`2A+B rarr C`
`DeltaH=400 kJ mol^(-1)` and `DeltaS=0.2 kJ K^(-1) mol^(-1)`
At what temperature will the reaction becomes spontaneous considering `DeltaH` and `DeltaS` to be contant over the temperature range.

Text Solution

Verified by Experts

`DeltaG = DeltaH -T DeltaS = 0`
`T = (DeltaH)/(DeltaS) = (400 kJ "mol"^(-1))/(0.2 kJ K^(-1) "mol"^(-1))`
` = 2000K`
`therefore` For the reaction to be spontaneous i.e for `DeltaG` to be -ve, T should be greater than 2000K.
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