Derive relationship between `DeltaH` and `DeltaU`.Give example when
(i) `DeltaH lt DeltaU`
(ii)`DeltaH = DeltaU`
(iii)`DeltaH gt DeltaU`

The relation between DeltaU and DeltaH :

The reaction in which DeltaH gt DeltaU is .

The enthalpy change for chemical reaction is denoted aas DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. For a reaction, 2X(s) +2Y(s) rarr 2C(l) +D(g), DeltaH at 27^(@)C is -28 kcal mol^(-1). DeltaU is ..... kcal mol^(-1)

The enthalpy change for chemical reaction is denoted as DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. For the change, C_("diamond") rarr C_("graphite"), DeltaH =- 1.89 kJ , if 6g of diamond and 6g of graphite are seperately burnt to yield CO_(2) the heat liberated in first case is

The enthalpy change for chemical reaction is denoted aas DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. Which of the following equations corresponds to the definition of enthalpy of formation at 298K ?