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Compute the heat of formation of liquid methyl alcohol in kilo joules per mole using the following data : Heat of vaporisation of liquid methyl alcohol : 38 kJ/mol.
Heat of formation of gaseous atoms from the elements in their standard states :
H = 218 kJ/mol,
C =` 715 ("kJ")/("mol")= and O = 249 ("kJ") /("mol")`.
Average bond energies,
`C - H = 415 kJ/mol, C - O = 356 (kJ)/(mol) and O-H = 436 (kJ)/(mol).`

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To compute the heat of formation of liquid methyl alcohol (CH₃OH) in kilojoules per mole, we will follow these steps: ### Step 1: Write the balanced chemical equation for the formation of methyl alcohol from its elements. The formation reaction for methyl alcohol from its elements in their standard states is: \[ C(s) + 2H_2(g) + \frac{1}{2}O_2(g) \rightarrow CH_3OH(l) \] ...
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Compute the heat of formation of liquie methyl alcohol is kilojoule per mol using the following data. Heat of vaporisation of liquid methyl alcohol =38kJ//mol . Heat of formation of gaseous atoms from the elements in their standard states :H=218kJ // mol, C=715kJ //mol, O=249kJ //mol. Average bond energies : C-H415kJ//mol, C-O 356kJ//mol, O-H 463kJ //mol.

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