The enthalpy change involved in the oxidation of glucose is `-2880 kJ mol^(-1)` 25% of this energy is available for muscular work. If 100 kJ of muscular work is neededto walk one kilometer, what is the maximum distance that a person will be able to walk after consuming 120 gm of glucose?

Explanation

Mass of glucose = 120 g
Moles of glucose = `(120)/(180) = 0.67` mol
Heat produced after eating 0.67 mol of glucose `= 0.67 xx 2880 = 1929.6 kJ`
Energy available for muscular work = `1929.6 xx (25)/(100) = 482.5 kJ`
Maximum distance that the person will walk = `(482.4)/(100) = 4.824` km.