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For an ideal gas expanding adiabatically...

For an ideal gas expanding adiabatically in vacuum,

A

`DeltaS (sys) = + ve, DeltaS(surr) = 0`

B

`DeltaS(sys) = 0, DeltaS(surr) = +ve`

C

`DeltaS(sys) = 0, DeltaS(surr) = 0`

D

`DeltaS(sys) = +ve, DeltaS(surr) = -ve`

Text Solution

Verified by Experts

The correct Answer is:
B
For adiabatic process, q = 0 and therefore `DeltaS(sys) = 0`
Irreversible process is accompained by increase of entropy and therefore `DeltaS (surr) = + ve`
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