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The enthalpy and entropy change for the ...

The enthalpy and entropy change for the reaction:
`Br_(2)(l) + CI_(2)(g) to 2BrCI(g)`
`30 kJ "mol"^(-1)` and `105 J K^(-1) "mol"^(-1)` respectively. The temperature at which the reaction will be in equilibrium is:

A

273 K

B

450 K

C

300 K

D

285.7 K

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaG = DeltaH - TDeltaS`
`0 = DeltaH - T DeltaS`
`TDeltaS = DeltaH`
`T = (DeltaH)/(DeltaS) = (30,000J "mol"^(-1))/(105 J K^(1) "mol"^(-1))` = 285.7 K`
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MODERN PUBLICATION-THERMODYNAMICS-Competition File MCQ
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