Four grams of graphite is burnt in a bomb calorimeter of heat capacity of `30 kJ K^(-1)` in excess of oxygen at 1 atmospheric pressure.The temperature rises from 300 to 304 K.What is the enthalpy of combustion of graphite (in `kJ "mol6(-1)`)?

Options

A. 360
B. 1440
C. `-360`
D. `-1440`

Answer

C

Explanation

`DeltaE = C xx Deltat xx (M)/(m)`
` = 30 kJ K^(-1) xx 4 xx (12)/(4)`
` = 360 kJ "mol"^(-1)`
`DeltaE = -360 kJ "mol"^(-1)`