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The DeltaG values for the following reac...

The `DeltaG` values for the following reactions at `800^(@)C` are
`S_(2)(g) + 2O_(2)(g) to 2SO_(2)(g) DeltaG = - 544 kJ`
`2Zn (s) + S_(2)(g) to 2ZnS(s) DeltaG = - 293 kJ`
`2Zn(s) + O_(2)(g) to 2ZnO(S) DeltaG = - 480 kJ`
The `DeltaG` for the reaction:
`2ZnS(s) + 3O_(2)(g) to 2ZnO(s) + 2SO_(2)(g)` is

A

`-731 kJ`

B

`-773 kJ`

C

`-229 kJ`

D

`-357 kJ`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ΔG for the reaction: \[ 2ZnS(s) + 3O_2(g) \rightarrow 2ZnO(s) + 2SO_2(g) \] we can use Hess's Law, which states that the total enthalpy change for a reaction is the sum of the enthalpy changes for the individual steps of the reaction. ### Step-by-Step Solution: 1. **Identify the Given Reactions and Their ΔG Values:** - Reaction 1: \[ S_2(g) + 2O_2(g) \rightarrow 2SO_2(g) \quad \Delta G_1 = -544 \, \text{kJ} \] - Reaction 2: \[ 2Zn(s) + S_2(g) \rightarrow 2ZnS(s) \quad \Delta G_2 = -293 \, \text{kJ} \] - Reaction 3: \[ 2Zn(s) + O_2(g) \rightarrow 2ZnO(s) \quad \Delta G_3 = -480 \, \text{kJ} \] 2. **Write the Target Reaction:** \[ 2ZnS(s) + 3O_2(g) \rightarrow 2ZnO(s) + 2SO_2(g) \] 3. **Manipulate the Given Reactions:** - We need to add Reaction 1 and Reaction 3, and reverse Reaction 2. - Reversing Reaction 2 gives: \[ 2ZnS(s) \rightarrow 2Zn(s) + S_2(g) \quad \Delta G = +293 \, \text{kJ} \] 4. **Add the Reactions:** - Adding Reaction 1 and Reaction 3: \[ S_2(g) + 2O_2(g) + 2Zn(s) + O_2(g) \rightarrow 2SO_2(g) + 2ZnO(s) \] This simplifies to: \[ S_2(g) + 3O_2(g) + 2Zn(s) \rightarrow 2SO_2(g) + 2ZnO(s) \] 5. **Subtract the Reversed Reaction 2:** - Now we subtract the reversed Reaction 2: \[ 2ZnS(s) \rightarrow 2Zn(s) + S_2(g) \] - This gives us: \[ 2ZnS(s) + 3O_2(g) \rightarrow 2ZnO(s) + 2SO_2(g) \] 6. **Calculate the ΔG for the Target Reaction:** - According to Hess's Law: \[ \Delta G_{\text{target}} = \Delta G_1 + \Delta G_3 - \Delta G_2 \] - Substituting the values: \[ \Delta G_{\text{target}} = (-544) + (-480) + 293 \] \[ \Delta G_{\text{target}} = -544 - 480 + 293 \] \[ \Delta G_{\text{target}} = -731 \, \text{kJ} \] ### Final Answer: The ΔG for the reaction \( 2ZnS(s) + 3O_2(g) \rightarrow 2ZnO(s) + 2SO_2(g) \) is \(-731 \, \text{kJ}\).
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The factor of DeltaG values is important in metallurgy. The DeltaG values for the following reactions at 800°C are given as : S_(2)(s) + 2O_(2)(g) to 2SO_(2)(g), DeltaG =-544 kJ 2Zn(s) + S_(2)(s) to 2ZnS(s), DeltaG=-293 kJ 2Zn(s) + O_(2)(g) to 2ZnO(s), DeltaG = -480 kJ Calculate the DeltaG for the reaction: 2ZnS(s) + 3O_(2)(g) to 2ZnO(s) + 2SO_(2)(g)

2Zn + O_(2) rightarrow 2ZnO, Delta G^(@) = -616 J 2Zn + S_(2) rightarrow 2ZnS, Delta G^(@) = -293 J S_(2) + 2O_(2) rightarrow 2SO_(2), Delta G^(@) = -408 J Delta G^(@) for the following reaction 2ZnS + 3O_(2) rightarrow 2ZnO+ 2 SO_(2) is

What is the equilibrium expression for this reaction ? 2ZnS(s)+3O_2(g) hArr 2ZnO(s)+2SO_2(g)

2C_"(s)" + O_(2(g)) to 2CO_((g)) , DeltaH = - 220 KJ, Which statement is correct for the reaction :-

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