Split the following redox reactions in the oxidation and reduction half reactions :
(i) `2K(s)+Cl_2(g) rarr 2KCl(s)`
(ii) `2Al (s) + 3Cu^(2+) (aq) rarr 2Al^(3+)(aq) +3Cu(s)`

Explanation

To split the given redox reactions into oxidation and reduction half-reactions, we will analyze each reaction step by step.

### (i) Reaction: `2K(s) + Cl_2(g) → 2KCl(s)`

**Step 1: Identify the oxidation states.**
- Potassium (K) in elemental form has an oxidation state of 0.
- In potassium chloride (KCl), potassium has an oxidation state of +1.
- Chlorine (Cl) in elemental form has an oxidation state of 0.
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