`C_(6)H_(5)N_(2)Cl + CuCN to C_(6)H_(5)CN + N_(2) + CuCl` is

Options

A. Balz-Schiemann
B. Gattermann reaction
C. Simonini reaction
D. Sandmeyer reaction

Answer

To solve the question regarding the reaction \( C_6H_5N_2Cl + CuCN \rightarrow C_6H_5CN + N_2 + CuCl \), we need to identify the type of reaction taking place. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Reactants
The reactants in the equation are:
- \( C_6H_5N_2Cl \) (Benzene diazonium chloride)
- \( CuCN \) (Copper(I) cyanide)

### Step 2: Analyze the Reaction
In this reaction, the benzene diazonium chloride is reacting with copper(I) cyanide. The diazonium salt contains a diazonium group (\( N_2^+ \)) which is known to be a good leaving group.

### Step 3: Determine the Products
The products of the reaction are:
- \( C_6H_5CN \) (Benzene cyanide or phenyl cyanide)
- \( N_2 \) (Nitrogen gas)
- \( CuCl \) (Copper(I) chloride)

### Step 4: Identify the Type of Reaction
This reaction is a substitution reaction where the diazonium group (\( N_2 \)) is replaced by the cyanide group (\( CN \)). This type of reaction is specifically known as the **Sandmeyer reaction**. In the Sandmeyer reaction, a diazonium salt is treated with a copper(I) salt in the presence of a nucleophile (in this case, cyanide ion from \( CuCN \)) to form a substituted aromatic compound.

### Conclusion
Thus, the reaction \( C_6H_5N_2Cl + CuCN \rightarrow C_6H_5CN + N_2 + CuCl \) is classified as a **Sandmeyer reaction**.

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