`CH_(3)C -= N overset(H_(2) // Ni)(to)` P, P will be?

Options

A. `CH_(3)CH_(2)NC`
B. `CH_(3)CH_(2)NH_(2)`
C. `CH_(3)NHCH_(3)`
D. `CH_(3)NH_(2)`

Answer

To solve the question regarding the reaction of CH₃C≡N with H₂ in the presence of nickel, we can break it down into several steps:

### Step 1: Identify the Reactants
The reactant given is CH₃C≡N, which is propionitrile (or methyl cyanide). It contains a carbon-nitrogen triple bond.

### Step 2: Understand the Reaction Conditions
The reaction is carried out in the presence of H₂ (hydrogen gas) and Ni (nickel) as a catalyst. This indicates that a hydrogenation reaction will occur.

### Step 3: Analyze the Hydrogenation Process
In hydrogenation, hydrogen is added across the multiple bonds (in this case, the triple bond) of the organic compound. Since CH₃C≡N has a triple bond between carbon and nitrogen, it will undergo hydrogenation.

### Step 4: Determine the Product
The triple bond (C≡N) will react with 2 moles of hydrogen (H₂) to convert the triple bond into a single bond (C-N). The reaction can be summarized as follows:
- CH₃C≡N + 2 H₂ → CH₃CH₂NH₂

This results in the formation of an amine. The product formed is ethylamine (or ethanamine).

### Step 5: Conclusion
Thus, the product P is ethanamine (CH₃CH₂NH₂).

### Final Answer
P = Ethanamine (CH₃CH₂NH₂)

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