In an experiment, DNA is treated with the compound which tends tol place itself amongst the stacks of nitrogenous base pairs. As a result of this, the distance between two consecutive base increases .From 0.34-0.44nm calculate the length of DNA double helix (Which has `2xx10^(9)bp) in the presence of saturating of this compound.

Explanation

`0.44 nm xx 2 xx 10^(@) = 0.88 xx 10^(@) nm or 0.88 m (1m = 10^(@) nm)`