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The expression [(sqrt2)^(sqrt2)]^(sqrt2)...

The expression `[(sqrt2)^(sqrt2)]^(sqrt2)` gives

A

a natural number

B

a integer and not a natural number

C

a rational number but not an integer

D

a real number but not a rational number

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \([( \sqrt{2} )^{\sqrt{2}}]^{\sqrt{2}}\), we can follow these steps: ### Step 1: Rewrite the expression We start with the expression: \[ [(\sqrt{2})^{\sqrt{2}}]^{\sqrt{2}} \] ### Step 2: Apply the power of a power rule Using the property of exponents that states \((a^m)^n = a^{m \cdot n}\), we can simplify the expression: \[ (\sqrt{2})^{\sqrt{2} \cdot \sqrt{2}} \] ### Step 3: Simplify the exponent Next, we simplify the exponent \(\sqrt{2} \cdot \sqrt{2}\): \[ \sqrt{2} \cdot \sqrt{2} = 2 \] Thus, the expression becomes: \[ (\sqrt{2})^2 \] ### Step 4: Simplify \((\sqrt{2})^2\) Now, we simplify \((\sqrt{2})^2\): \[ (\sqrt{2})^2 = 2 \] ### Final Answer Therefore, the expression \([( \sqrt{2} )^{\sqrt{2}}]^{\sqrt{2}}\) evaluates to: \[ 2 \]
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