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A box contains 2 blue caps, 4 red caps, ...

A box contains 2 blue caps, 4 red caps, 5 green caps and 1 yellow cap.
if two caps are picked at random, what is the probability that both are blue?

A

`1/6`

B

`1/10`

C

`1/12`

D

None of the above

Text Solution

AI Generated Solution

The correct Answer is:
To find the probability that both caps picked are blue, we can follow these steps: ### Step 1: Determine the total number of caps First, we need to find the total number of caps in the box. The box contains: - 2 blue caps - 4 red caps - 5 green caps - 1 yellow cap **Total number of caps = 2 (blue) + 4 (red) + 5 (green) + 1 (yellow) = 12 caps.** ### Step 2: Calculate the total number of ways to pick 2 caps Next, we need to calculate the total number of ways to choose 2 caps from the 12 caps. This can be calculated using the combination formula: \[ \text{Total ways to pick 2 caps} = \binom{n}{r} = \frac{n!}{r!(n-r)!} \] Where \( n \) is the total number of caps (12) and \( r \) is the number of caps to pick (2). \[ \binom{12}{2} = \frac{12!}{2!(12-2)!} = \frac{12 \times 11}{2 \times 1} = 66 \] ### Step 3: Calculate the number of ways to pick 2 blue caps Now, we need to find the number of ways to choose 2 blue caps from the 2 available blue caps. Again, we use the combination formula: \[ \text{Ways to pick 2 blue caps} = \binom{2}{2} = \frac{2!}{2!(2-2)!} = 1 \] ### Step 4: Calculate the probability Finally, we can calculate the probability that both caps picked are blue. The probability \( P \) can be calculated as: \[ P(\text{both caps are blue}) = \frac{\text{Number of ways to pick 2 blue caps}}{\text{Total ways to pick 2 caps}} = \frac{1}{66} \] ### Final Answer Thus, the probability that both caps picked are blue is: \[ \frac{1}{66} \] ---
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