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The ratio of the areas of the circumcirc...

The ratio of the areas of the circumcircle and the incircle of a square is

A

`2 : 1`

B

`1 : 2`

C

`a//2 : 1`

D

`1//a2`

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The correct Answer is:
To find the ratio of the areas of the circumcircle and the incircle of a square, we can follow these steps: ### Step 1: Understand the Shapes A square has both a circumcircle (the circle that passes through all four vertices) and an incircle (the circle that is tangent to all four sides). ### Step 2: Define the Side Length Let the side length of the square be denoted as \( s \). ### Step 3: Calculate the Area of the Incircle The radius of the incircle is equal to half the side length of the square. Therefore, the radius \( r \) of the incircle is: \[ r = \frac{s}{2} \] The area \( A_{in} \) of the incircle is given by the formula: \[ A_{in} = \pi r^2 = \pi \left(\frac{s}{2}\right)^2 = \pi \frac{s^2}{4} \] ### Step 4: Calculate the Area of the Circumcircle The radius of the circumcircle is equal to half the diagonal of the square. The diagonal \( d \) of the square can be calculated using the Pythagorean theorem: \[ d = s\sqrt{2} \] Thus, the radius \( R \) of the circumcircle is: \[ R = \frac{d}{2} = \frac{s\sqrt{2}}{2} \] The area \( A_{circ} \) of the circumcircle is: \[ A_{circ} = \pi R^2 = \pi \left(\frac{s\sqrt{2}}{2}\right)^2 = \pi \frac{2s^2}{4} = \pi \frac{s^2}{2} \] ### Step 5: Find the Ratio of the Areas Now we can find the ratio of the area of the circumcircle to the area of the incircle: \[ \text{Ratio} = \frac{A_{circ}}{A_{in}} = \frac{\pi \frac{s^2}{2}}{\pi \frac{s^2}{4}} = \frac{\frac{s^2}{2}}{\frac{s^2}{4}} \] When we simplify this, the \( \pi \) and \( s^2 \) cancel out: \[ \text{Ratio} = \frac{1/2}{1/4} = \frac{1}{2} \times \frac{4}{1} = 2 \] ### Step 6: Final Ratio Thus, the ratio of the areas of the circumcircle to the incircle of a square is: \[ \text{Ratio} = 2:1 \] ### Conclusion The final answer is that the ratio of the areas of the circumcircle and the incircle of a square is \( 2:1 \). ---
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