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A particle projected horizontally from t...

A particle projected horizontally from the top of an inclined plane inclined at an angle `theta` with the horizontal with velocity u. What is the distance along the plane from the point of projection at which the projectile strikes the inclined plane ?

A

`(2u^(2)tan(theta))/g`

B

`1/2 (u^(2)tan(theta))/g`

C

`(2u^(2)tan^(2)(theta))/g`

D

`(2u^(2)tan(theta)sec theta)/g`

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The correct Answer is:
D
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