A glass prism of angle `60^(@) and mu_(g)` = 1.66 is immersed in a liquid of `mu_(1)` = 1.33. Find the angle of minimum deviation for a parallel beam of light passing through prism.

Options

A. `9.4^(@)`
B. `17.2^(@)`
C. `12.6^(@)`
D. `9.2^(@)`

Answer

B

Explanation

(b) `.^(w)mu_(g)=(.^(a)mu_(g))/(.^(a)mu_(w))=(1.66)/(1.33)`
When prism is dipped in water and `delta_(m)` is minimum deviation, then
`.^(w)mu_(g)=(sin((A+deltam)/(2)))/((sinA)/(2))`
` = (1.66)/(1.33)`
Solving, we get, `delta_(m) = 17.2^(@)`