Two lenses (1) and (2) with `R_(1) = R_(2) = 0.20 m` each are made from glasses with `mu_(1) = 1.2 and mu_(2)` = 1.6 respectively. The two lenses with a separation of 0.345 m are submerged in a liquid with `mu_(1) = 1.4`. The focal lenghts of (1) and (2) are found. An object is placed at a distance of 1.3m from lens 1.
The location of the image while system remains inside the liquid is :

Options

A. 6.52 m
B. 5.60 m
C. 0.56 m
D. 12.67 cm

Answer

B

Explanation

(b) for lens 1 , u = - 13 m
`f_(1) = - 70 cm`
= - 70 m
`(1)/(v) - (1)/(u) = (1)/(f_(1))`
u = - 0.455 m
for lens 2 : u = 0.345 - 0.45 = - 0.8 m
`(1)/(v) - (1)/(u) = (1)/(f_(2)) v = 5.6`