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If sin^(2)theta - 2 sin theta - 1 = 0 is...

If `sin^(2)theta - 2 sin theta - 1 = 0` is to be satisfied for exactly 4 distrinct value of `theta in[0,npi],n in N`, then the least value of n is :

A

2

B

6

C

4

D

1

Text Solution

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The correct Answer is:
C
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