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In a DeltaPQR3sin p + 4cosQ = 6 and 4sin...

In a `DeltaPQR``3sin p + 4cosQ = 6` and `4sinQ + 3cosP = 1`, then the angle R is equal to :

A

`(5pi)/6`

B

`(pi)/6`

C

`(pi)/4`

D

`(3pi)/6.`

Text Solution

Verified by Experts

The correct Answer is:
B
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