The number of atoms present in 1 g of hydrogen gas is the same as are present in

Options

A. 0.4 g of He
B. 22 g of `CO_2`
C. 6 g of `H_2O`
D. 12 g of C

Answer

C

Explanation

2g of `H_2` gas ` = 6 xx 10^23` molecules
` = 6 xx 10^23 xx 2 ` atoms
1 g of `H_2` gas ` = (6 xx 10^23 xx 2)/(2) = 6 xx 10^23` atoms
Now 6g of `H_2O = (6 xx 10^23)/(18) xx 6` molecules
` = (6 xx 10^23 xx 6 xx 3)/(18) `
` = 6 xx 10^23` molecules