If `CH_(3)COOH + OH^(-) rarr CH_(3)COO^(-) + H_(2)O + x kJ`
`H^(+) + OH^(-) rarr H_(2)O + y kJ`
The enthalpy change for the reaction :
`CH_(3)COOH rarr CH_(3)COO^(-) + H^(+)` is

Options

A. x + y
B. x - y
C. y - x
D. `x - y//2`

Answer

C

Explanation

(i) `CH_(3)COOH + OH^(-) rarr CH_(3)COO^(-) + H_(2)O, Delta H = -x`
(ii) `H^(+) + OH^(-) rarr H_(2)O, Delta H = -y` Subtracting (ii) from (i),
`CH_(3)COOH rarr CH_(3)COO^(-) + H^(+), Delta H = -x + y "or" = y - x`