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For a reaction at equilibrium, the parti...

For a reaction at equilibrium, the partial pressure of B is found to be one fourth of the partial pressure of A. The value of `Delta G^(theta)` of the reaction `A rarr B` is

A

`-RT log 4`

B

`2.303 RT log 4`

C

`-2.303 RT log 1/ 4`

D

`2.303 R log 4`

Text Solution

Verified by Experts

The correct Answer is:
B
`K = (1)/(4)`
:. `Delta G = - 2.303 RT log. (1)/(4)`
`= 2.303 RT log 4`
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