For a particular reversible reaction at temperature T. `Delta H and Delta S` were found to be both +ve. If `T_(e)` is the temperature at equilibrium, the reaction would be spontaneous when

Options

A. `T_(e)` is five times T
B. `T = T_(e)`
C. `T_(e) gt T`
D. `T gt T_(e)`

Answer

D

Explanation

`Delta G = Delta H - T Delta S`
At equilibrium, `Delta G = 0`
`0 = Delta H - T Delta S`
or `T_(e) Delta S = Delta H`
`T_(e) = (Delta H)/(Delta S)`
Since it is an endothermic reaction, its is favoured by high temperature so that `T gt T_(e)`.