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The amount of solute required to prepare...

The amount of solute required to prepare 10 L of a decimolar solution is :

A

0.01 mol

B

0.2 mol

C

0.1 mol

D

1 mol

Text Solution

Verified by Experts

The correct Answer is:
D
Molarity `=("Moles of solute")/("Volume")xx1000`
Moles of solute `=("Molarity" xx "Volume")/(1000)=(0.1xx10000)/(1000)=1`
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